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MathematicsMadrid 2026Question 1Free lesson

Rank with a parameter and a matrix equation

Matrices: why the determinant decides the rank, why a minor is needed, and why we multiply by the inverse on the left

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Problem statement

Given the real matrix $A=\begin{pmatrix}1&\lambda-2&\lambda\\0&1&\lambda-1\\1&0&1\end{pmatrix}$, find:

a) (1 mark) Discuss the rank of $A$ as a function of the parameter $\lambda$.

b) (1 mark) For the case $\lambda=2$, solve the matrix equation $A^2-AX=I$, where $I$ is the identity matrix of order $3$.

Source: Madrid university entrance exam (PAU, Spain) · 2025-2026 · Ordinary session · Mathematics · Question 1. Official exam set by the public universities of the Community of Madrid, to whom it belongs; translated from Spanish and reproduced with its source in order to explain it for teaching purposes.

What this lesson answers

  1. What are we asked, and what can we anticipate without calculating?
  2. Why does the determinant decide whether the rank is 3?
  3. If the determinant is zero, why is the rank 2 and not 1?
  4. Why can't we “divide by A”, and on which side do we multiply?
  5. Where does the inverse come from, and what matrix is X?
  6. Another way: row reduction for the rank, and the equation without simplifying
  7. The answers and how to check them
  8. Common mistakes to avoid
  9. Exam tips
  10. If you want top marks

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