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Technical DrawingMadrid 2026Question 1.1Free lesson

Inverse arc under an inversion

Where the centre of inversion is, what its power is, and why each construction line is the way it is

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Problem statement

Question 1.1 (2.5 marks; you answer one of the two questions, 1.1 or 1.2). Determine the inverse arc of $AB$ under the inversion that transforms circle $c$ into circle $c'$. Explain the basis of the construction used.

Figure in the statement: circle $c$, with centre $C$, lies inside the larger circle $c'$, and the two are internally tangent at a point $P$ on the line of centres. Point $B$ is the end of $c$ opposite $P$, and $A$ is the point of $c$ on the perpendicular to that line through $C$. Arc $AB$, drawn with a thick line, is the quarter circle from $A$ to $B$.

Data read from the figure (the statement does not write them): the centre of $c'$ coincides with $B$ and the radius of $c'$ is twice that of $c$. We take $r=[[r]]$ drawing units for $c$ and $r'=[[rp]]$ for $c'$.

Source: Madrid university entrance exam (PAU, Spain) · 2025-2026 · Ordinary session · Technical Drawing · Question 1.1. Official exam set by the public universities of the Community of Madrid, to whom it belongs; translated from Spanish and reproduced with its source in order to explain it for teaching purposes.

What this lesson answers

  1. What data do we have, and which properties of inversion will we use?
  2. Where is the centre of inversion? A centre of homothety
  3. What is the power of the inversion?
  4. Where does the inverse of point A fall?
  5. What does arc AB become?
  6. Another way: build the inverse using only the power, and check
  7. Common mistakes to avoid
  8. Exam tips
  9. If you want top marks

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