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Technology and EngineeringMadrid 2026Question 4.1Free lesson

Parallel AC circuit

From the capacitor current to the voltage, the powers and the generator current: why it is solved this way

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Problem statement

In the circuit shown, the ammeter reading, which is the RMS value of the current through the capacitor, is $[[Ic]]$ A. The circuit has three branches in parallel connected to the generator $E$: one with $R_1$ and $R_2$ in series, another with the inductors $L_1$ and $L_2$ in series, and another with the ammeter and the capacitor $C$ in series.

Data: $R_1 = [[R1]]\ \Omega$, $R_2 = [[R2]]\ \Omega$, $X_{L1} = [[XL1]]\ \Omega$, $X_{L2} = [[XL2]]\ \Omega$, $X_C = [[XC]]\ \Omega$.

Calculate:

a) (0.4 marks) The RMS value of the electromotive force $E$.

b) (0.3 marks) The RMS value of the current through the resistors.

c) (0.3 marks) The RMS value of the current through the inductors.

d) (0.6 marks) Active, reactive and apparent power delivered by the generator $E$.

e) (0.4 marks) The RMS value of the current through the generator $E$.

Source: Madrid university entrance exam (PAU, Spain) · 2025-2026 · Ordinary session · Technology and Engineering · Question 4.1. Official exam set by the public universities of the Community of Madrid, to whom it belongs; translated from Spanish and reproduced with its source in order to explain it for teaching purposes.

What this lesson answers

  1. What does the circuit tell us before any calculation?
  2. a) Where does the electromotive force come from, if we only know one current?
  3. b and c) Why does each branch let through a different current at the same voltage?
  4. d) Why does the active power add, the reactive subtract, and the apparent is not the sum of anything?
  5. e) Why is the generator current not the sum of the three?
  6. Is there another route that gives the same current?
  7. The five answers and how to check them
  8. Common mistakes to avoid
  9. Exam tips
  10. If you want top marks

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